(9x-2y)^1/3=x^2

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Solution for (9x-2y)^1/3=x^2 equation:


x in (-oo:+oo)

((9*x-(2*y))^1)/3 = x^2 // - x^2

((9*x-(2*y))^1)/3-x^2 = 0

(9*x-2*y)/3-x^2 = 0

(9*x-2*y)/3+(3*(-x^2))/3 = 0

3*(-x^2)+9*x-2*y = 0

9*x-3*x^2-2*y = 0

(9*x-3*x^2-2*y)/3 = 0

(9*x-3*x^2-2*y)/3 = 0 // * 3

9*x-3*x^2-2*y = 0

9*x-3*x^2-2*y = 0

DELTA = 9^2-(-3*(-2)*4*y)

DELTA = 81-24*y

81-24*y = 0

81-24*y = 0 // - 81

-24*y = -81 // : -24

y = -81/(-24)

y = 27/8

DELTA = 0 <=> t_3 = 27/8

x = -9/(-3*2) i y = 27/8

x = 3/2 i y = 27/8

( x = ((81-24*y)^(1/2)-9)/(-3*2) or x = (-(81-24*y)^(1/2)-9)/(-3*2) ) i y > 27/8

( x = ((81-24*y)^(1/2)-9)/(-6) or x = ((81-24*y)^(1/2)+9)/6 ) i y > 27/8

y-27/8 > 0

y-27/8 > 0 // + 27/8

y > 27/8

x in { 3/2, ((81-24*y)^(1/2)-9)/(-6), ((81-24*y)^(1/2)+9)/6 }

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